FizzBuzz (the Classic Practice Problem)

In this lesson you will solve the classic FizzBuzz problem in Kotlin, combining conditionals with a loop. This is for anyone searching for "Kotlin FizzBuzz implementation".

FizzBuzz is a staple of programming practice. You print the numbers in order, but print "Fizz" for multiples of 3, "Buzz" for multiples of 5, and "FizzBuzz" for multiples of both. It is perfect practice for conditionals.

The sample code loops from 1 to 15 with a for statement and uses a condition-less when expression, checking i % 15 == 0 first so multiples of 15 take priority. The order of the checks is what makes it work.

A common stumbling block for beginners is exactly that ordering. Check for multiples of 3 and 5 first and a multiple of 15 prints only "Fizz", so you have to test the strictest condition first.

It is simple, yet it breaks if you get the order wrong, which is why it is a favourite for interviews and training. It is also ideal for practising the remainder operator (%) while cementing the basics of conditionals.

📖 Reference code

fun main() {
    for (i in 1..15) {
        when {
            i % 15 == 0 -> println("FizzBuzz")
            i % 3 == 0 -> println("Fizz")
            i % 5 == 0 -> println("Buzz")
            else -> println(i)
        }
    }
}

✍️ Your code

Type your code, then press "Run"

🧪 This site can't compile or run Kotlin directly, so it checks on the spot whether what you typed matches the reference code (scoring happens entirely in your browser — nothing is sent anywhere).