FizzBuzz (the Classic Practice Problem)

In this lesson you will solve the classic FizzBuzz problem in Go, combining conditionals with a loop. This is for anyone searching for "Go FizzBuzz implementation".

FizzBuzz is a staple of programming practice. You print the numbers in order, but print "Fizz" for multiples of 3, "Buzz" for multiples of 5, and "FizzBuzz" for multiples of both. It is perfect practice for conditionals.

The sample code loops from 1 to 15 and checks i%15 == 0 first, so multiples of 15 take priority, then checks for multiples of 3 and 5. The order of the checks is what makes it work.

A common stumbling block for beginners is exactly that ordering. Check for multiples of 3 and 5 first and a multiple of 15 prints only "Fizz", so you have to test the strictest condition first.

It is simple, yet it breaks if you get the order wrong, which is why it is a favourite in interviews and training for gauging how well someone has grasped the basics. It is also ideal for practising the remainder operator (%) while cementing conditionals.

📖 Reference code

package main

import "fmt"

func main() {
	for i := 1; i <= 15; i++ {
		if i%15 == 0 {
			fmt.Println("FizzBuzz")
		} else if i%3 == 0 {
			fmt.Println("Fizz")
		} else if i%5 == 0 {
			fmt.Println("Buzz")
		} else {
			fmt.Println(i)
		}
	}
}

✍️ Your code

Type your code, then press "Run"

🧪 This site can't compile or run Go directly, so it checks on the spot whether what you typed matches the reference code (scoring happens entirely in your browser — nothing is sent anywhere).